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0=24x^2-10x-1
We move all terms to the left:
0-(24x^2-10x-1)=0
We add all the numbers together, and all the variables
-(24x^2-10x-1)=0
We get rid of parentheses
-24x^2+10x+1=0
a = -24; b = 10; c = +1;
Δ = b2-4ac
Δ = 102-4·(-24)·1
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*-24}=\frac{-24}{-48} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*-24}=\frac{4}{-48} =-1/12 $
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